3. In an experiment samples of beatles were exposed for five hours to different concentrations of gaseous carbon disulph
Posted: Mon Nov 15, 2021 10:24 am
11.232 on 6 degrees of freedom Residual deviance: AIC: 41.43 Number of Fisher Scoring iterations: 4 > anova (out1) Analysis of Deviance Table Model: binomial, link: E Response: c1 Terms added sequentially (first to last) Df Deviance Resid. Df Resid. Dev NULL 7 284.202 Dose 1 F 6 11.232 > vcov (out1) (Intercept) Dose (Intercept) 26.83966 -15.082090 Dose -15.08209 8.480525 (a) Determine the missing information indicated by the letters A,B,C,D, E and F. Note that for E you are required to specify the link function. [6 Marks) (b) Explain what is meant by the Null Deviance. (2 Marks) (c) Explain what is meant by the Residual Deviance. [2 Marks] (d) What conclusions do you draw from the above R output? What would be your next steps in the R analysis? [4 Marks) (e) Calculate the fitted value for the third observation in the dataset (see the third row in the data file which is printed out near the top of the block of R code). [3 Marks]
= (f) Calculate an estimate of the variance of the fitted linear predictor n3 = @ x; for the third observation in the dataset. [ 4 Marks] (g) Using the delta method, find an approximate 95% confidence in- terval for the probability that a beatle is killed by exposure for five hours to a dose of 1.7552 units of gaseous carbon disulphide. [4 Marks]