- For This Question There Is No Try A Similar Option You Will Get 10 Tries To Answer It Correctly Consider A Family Wi 1 (45.76 KiB) Viewed 28 times
For this question there is no "try a similar" option. You will get 10 tries to answer it correctly. Consider a family with 4 children. Assume the probability that one child is a boy is 0.5 and the probability that one child is a girl is also 0.5, and that the events boy and girls are independent. a) There are 16 equally likely outcomes of the sex of the four children. Let M represent the child is male, and F represent the child is female. If we list the sex of the four children from oldest to youngest, here are two possible outcomes: MFFM. This is short for first child is male, second child is female, third child is female, fourth child is male. FFMM - This is short for first child is female, second child is female, third child is male, fourth child is male List the remaining 14 possible outcomes using this format. Separate them by commas. MMMM, MMME, MMEM, MMFF, MEMM, MFMF, MFFE, FMMM, EMMF, EMFM, FMFF, FEME,FFFM, FFFF 5 b) What is the probability that all 4 children are male? 4 16 C) The complement of the event "all four children are male" is "at least one of the children is female. Use this information to compute the probability that at least one child is female.