In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6984 subjects randoml
Posted: Wed May 11, 2022 3:04 pm
- In A Study Of Cell Phone Usage And Brain Hemispheric Dominance An Internet Survey Was E Mailed To 6984 Subjects Randoml 1 (355.48 KiB) Viewed 24 times
Because the P-value is (greater than/less than) the
significance level (reject/fail to reject) the null hypothesis.
There is (sufficient/insufficient) evidence to support the claim
that the return rate is less than 20%.
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6984 subjects randomly selected from an online group involved with ears. There were 1318 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. A. Ho: p = 0.2 H :p<0.2 B. Ho:p> 0.2 Hy: P = 0.2 0C. Ho: p < 0.2 Hy: P = 0.2 D. Ho:p*0.2 Hy: p = 0.2 O E. Ho: p = 0.2 Hy: P80.2 0 F. Ho: p = 0.2 H :p>0.2 The test statistic is z= - 2.36. (Round to two decimal places as needed.) The P-value is 0.008 (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.