Answer Happy

2 A promising start-up wants to compete in the cell phone market. The start-up believes that the battery life of its cell phone is more than two hours longer than the leading product. A recent sample of 120 units of the leading product provides a mean battery life of 6 hours and 39 minutes with a standard deviation of 35 minutes. A similar analysis of 101 units of the start-up's product results in a mean battery life of 9 hours and 2 minutes and a standard deviation of 46 minutes. It is not reasonable to assume that the population variances of the two products are equal. 2.5 points All times are converted into minutes. Let new products and leading products represent population 1 and population 2, respectively. (You may find it useful to reference the appropriate table: z table or t table) a. Set up the hypotheses to test if the new product has a battery life more than two hours longer than the leading product. Print References Ho: 41 - H2 = 120; HA: M1 - 42 7 120 O Ho: 41 - M2 = 120; HA: 41 - M2 <120 Ho: 41 - H2 = 120; HA: H1 - H2> 120 b-1. Calculate the value of the test statistic. (Round final answer to 3 decimal places.) Test statistic

Homework 10: Online i Saved Help Save & Exit Sub b-2. Find the p-value. 2 2.5 points O p-value < 0.01 O p-value Picture 0.10 O 0.05 Picture p-value < 0.10 O 0.025 Picture p-value < 0.05 O 0.01 Picture p-value < 0.025 Print References b-3. At the 5% significance level, is the claim that the new product has, on average, a battery life of more than two hours longer than the leading product is supported by the sample data? HO. The claim that the new product has, on average, a battery life of more than two hours longer than the leading product is by the sample data at the 5% significance level.