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A Washington Post-ABC News poll conducted in October 2009 surveyed a random sample of 1004 adults in the United States.

Posted: Wed May 11, 2022 1:33 pm
by answerhappygod
A Washington Post Abc News Poll Conducted In October 2009 Surveyed A Random Sample Of 1004 Adults In The United States 1
A Washington Post Abc News Poll Conducted In October 2009 Surveyed A Random Sample Of 1004 Adults In The United States 1 (42.56 KiB) Viewed 101 times
A Washington Post-ABC News poll conducted in October 2009 surveyed a random sample of 1004 adults in the United States. Of these people, 713 said they would support federal legislation putting limits on the amounts that top executives are paid at companies that receive emergency government loans. .. Part 1. What PROPORTION of adults in the sample supported this federal legislation? (decimal only, round to two decimal places) Part 2. Suppose we want to test whether the percentage of all U.S. adults who supported the legislation is less than 75%. The appropriate hypotheses are: O A. Ho: p=75 vs. Hy :p < 75 OB. Ho:p<75 vs. Hy : p = 75 0C. Hop< 75 vs Hip = 75 OD. Ho: p= 75 vs. Hy :p < 75 Part 3. The test statistic is -2.93. What is the p-value? (decimal only, 4 decimal places) Part 4. At the .05 level of significance, we O A. Reject the null hypothesis. We do not have sufficient evidence to say the percentage is less than 75%. OB. Reject the null hypothesis. We have sufficient evidence to say the percentage is less than 75%. OC. Do not reject the null hypothesis. We do not have sufficient evidence to say the percentage is less than 75%. OD. Do not reject the null hypothesis. We have sufficient evidence to say the percentage is less than 75%. Part 5. Suppose this had been a two-tailed test. What would the p-value be in that case? (decimal only, 4 decimal places)