6. [-/10 Points] DETAILS ASWSBE14 12.TB.1.002. MY NOTES ASK YOUR TEA You may need to use the appropriate appendix table
Posted: Wed May 11, 2022 11:14 am
6. [-/10 Points] DETAILS ASWSBE14 12.TB.1.002. MY NOTES ASK YOUR TEA You may need to use the appropriate appendix table or technology to answer this question. The following table shows the results of a study on smoking and three illnesses. We are interested in determining if the proportions of smokers in the three categories are different from each other. (Let p, and P3, represent the proportions of smokers with emphysema, heart problems, and cancer respectively. Use a 0.05 level of significance.) Emphysema Heart problem Cancer Total Smoker 145 75 95 315 Non-smoker 55 140 490 685 Total 200 215 585 1,000 (a) Provide the null and alternative hypotheses. O Ho: All population proportions are not equal. Ha: P1 = P2 = P3 O Ho: P1 = P2 = P3 Ha: Not all population proportions are equal. O Ho: Not all population proportions are equal. Ha: P1 = P2 = P3 O Ho: P1 = P2 = P3 Ha: All population proportions are not equal.
(b) Determine the expected frequencies. Emphysema Heart problem Cancer Total Smoker 315 Non-smoker 685 Total 200 215 585 1,000 (c) Compute the sample proportions. (Round your answers to four decimal places.) = P1 P2 = P3 = (d) Compute the critical values (CV;j). (Round your answers to five decimal places.) CV 12 CV 13 = CV 23 is CV 12 (e) Give your conclusions by providing numerical reasoning. (Round your numerical answers to four decimal places.) P1 --Select--- v differ significantly from P2, since 121 - Pz! = Select--- P1 -Select--- v differ significantly from P3, since 101 - P31 = CV 13: P2 differ significantly from P3, since 1P2 - P31 = | - = is Select--- Select-- is Select--- CV 23
(b) Determine the expected frequencies. Emphysema Heart problem Cancer Total Smoker 315 Non-smoker 685 Total 200 215 585 1,000 (c) Compute the sample proportions. (Round your answers to four decimal places.) = P1 P2 = P3 = (d) Compute the critical values (CV;j). (Round your answers to five decimal places.) CV 12 CV 13 = CV 23 is CV 12 (e) Give your conclusions by providing numerical reasoning. (Round your numerical answers to four decimal places.) P1 --Select--- v differ significantly from P2, since 121 - Pz! = Select--- P1 -Select--- v differ significantly from P3, since 101 - P31 = CV 13: P2 differ significantly from P3, since 1P2 - P31 = | - = is Select--- Select-- is Select--- CV 23