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Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 43 of the 50 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 78 of the 93 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. . a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? A. Ho: P1 P2 HP1 = P2 OB. Ho: P1 P2 H: P1 P2 E Ho: P = P2 HP P2 C. HOP SP2 HP, #P2 OF HO P = P2 HP: <P2 Mo. Ho: P1 P2 H:P4 *P2 Identify the test statistic. . z= (Round to two decimal places as needed.) Identify the P-value P-value- (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is less than the significance level of a=0,01, 50 reject the null greater than fail to reject hypothesis. There is no sufficient evidence to support the claim that echinacea treatment is has an effect h. Test the claim by constructing an appropriate confidence interval The 99% confidence interval is <p-p<0. Round in the decimal law and (Round to three decimal places as needed.) What is the conclusion based on the confidence interval? Because the confidence interval limits include, there does not appear to be a do not include does significant difference between the two proportions. There is not evidence to support the is claim that echinacea treatment has an effect.