Answer Happy

We need to confirm that the m and b we found will give a minimum of the sum of the squared residules, E(m,b), and not a maximum or saddle point. There is a second derivative test for functions of two variables, and three conditions must be met. E(m,b) will have a a minimum for particular values of m and b: a. aE aE The first partial derivatives are zero; = 0 and дт partial derivatives equal to 0 in question (3.) in Part 1. = 0. We've already met this condition since we set the дт b. The determinant of the Hessian matrix must be positive. The Hessian matrix is defined in terms of second partial derivatives 32 E 02 E Əm2 дедь H= 22 E Labām ab2 22 E c. The second partial derivative with respect to either variable must be positive. 1. Show that the determinant of the Hessian Matrix can be expressed as D = 4n Στ2 – 4(Σα)?