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Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.10 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. O A. Ho H 712 H₂ H > H2 OB. HoH SH2 H:H1>H2 More Info O C. Ho- H - P2 H₂ : H₂ & 12 OD. Ho H4 =12 H:H1 H2 The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. City #1 105 86 121 118 101 104 213 146 290 100 302 145 City #2 117 91 100 85 89 107 110 111 116 133 101 209 O A. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. OB. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. O C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. OD. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. Print Done