Question 11 Find an equation in x and y for the line tangent to the curve y x(t) = 4t - 1, y(t) = 14 at the point (3, 1)
Posted: Wed May 11, 2022 5:03 am
Question 11 Find an equation in x and y for the line tangent to the curve y x(t) = 4t - 1, y(t) = 14 at the point (3, 1). a) Ox - 4y = 0 b) O 4 x - 4y - 8 = 0 c) O4x + 4y + 16 = 0 d) O 4x + 4y - 8 = 0 e) O-4x + 4y - 8 = 0 Review Later