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Question 3 < > The function f(3) = 2.1 42.12 + 2700 + 11 has one local minimum and one local maximum. This function has a local minimum at I equals with value and a local maximum at I equals with value Submit Question

Score: 0/13 0/13 answered Question 4 < > Given the function 9(T) = 6.13 – 45x2 + 72.r, find the first derivative, g'(x). g'(x) = Notice that g'(x) = 0 when I = 4, that is, g'(4) = 0. Now, we want to know whether there is a local minimum or local maximum at 2 = 4, so we will use the second derivative test. Find the second derivative, 3"(x). 9"(x) = Evaluate 3" (4) 3"(4) = Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at X = 4? [Answer either up or down -- watch your spelling!!] At I = 4 the graph of g(2) is concave Based on the concavity of g(2) at x = 4, does this mean that there is a local minimum or local maximum at x = 4? [Answer either minimum or maximum -- watch your spelling!!) At = 4 there is a local Submit Question