ses is е 29. The inverse Laplace transform of F(s) $2 + 2s + 5 A. U1(t) (e-t cos 2(t – 1)) – sin 2(t – 1) B. (e=t+1 cos

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ses is е 29. The inverse Laplace transform of F(s) $2 + 2s + 5 A. U1(t) (e-t cos 2(t – 1)) – sin 2(t – 1) B. (e=t+1 cos 2(t – 1)) – že=t+1 sin 2(t – 1) C. Ui(t) (et-1 cos 2(t – 1)) – sin 2(t – 1) D. uo(t) (e-* cos 2t) – et sin 2t E. uj(t) (e-++1 cos 2(t – 1) - {e=t+l sin 2(t – 1)) t 1že –1 2 e e -t1