Answer Happy

Posted: **Tue May 10, 2022 8:30 pm**

: 2t 1 27 Solve Y 3y 2y 4u1 T Y 0 0 Y 0 1 A Ui T 2 4e T 1 2e 2 T 1 B Ui T 2 4e T 1 (83.7 KiB) Viewed 34 times

= -2t - -1) 27. Solve y" + 3y' + 2y = 4u1(t)y(0) = 0, y'(0) = 1 A. ui(t) (2 – 4e-(t-1) + 2e-2(t-1)) B. ui(t) (2 – 4e-(t-1) +2e=2(t-1)) +et - e=24 C. uo(t) (2 – 4e-(t-1) + 2e-2(t-1)) +et D. (2 – 4e-(6-1) + 2e +244-1)) +e+ -- 2-24 E. et 2t -2t - e