Match the solution curve with one of the differential equations. у. Oy" - 4y' - 5y = 0 Oy" + 2y' + 2y = 0 Oy" + y = 0 y"

[answerhappygod]

1 (27.03 KiB) Viewed 18 times

Match the solution curve with one of the differential equations. у. Oy" - 4y' - 5y = 0 Oy" + 2y' + 2y = 0 Oy" + y = 0 y" + 4y = 0 y" – 7y' + 12y = 0 Oy" + 2y' + y = 0 + + Explain your reasoning. Assume that k, kq, and ky are all positive.) The differential equation should have the form y" + k2y = 0 where k = 2, so that the period of the solution is it. The auxiliary equation should have one positive and one negative root, so that the solution has the form ceky* + cze-kzx. The differential equation should have the form y" + k2y = 0 where k = 1, so that the period of the solution is 27. The auxiliary equation should have a pair of complex roots a + Bi where a < 0, so that the solution has the form ear( cos(Bx) + C2 sin(Bx)). +