(a) Use the binomial series to expand 3 x2 . 3+3 § 1-3-5 (2n – 1) , 2n n=1 21.n! 00 3+3 3.5.7... (2n + 1) ys 21.n! n=1 0
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(a) Use the binomial series to expand 3 x2 . 3+3 § 1-3-5 (2n – 1) , 2n n=1 21.n! 00 3+3 3.5.7... (2n + 1) ys 21.n! n=1 0
(a) Use the binomial series to expand 3 x2 . 3+3 § 1-3-5 (2n – 1) , 2n n=1 21.n! 00 3+3 3.5.7... (2n + 1) ys 21.n! n=1 00 3+3 2.4.6. 21.n! n=1 3 ...+(21) x2 3+3 Σ 1.3.5.... (2n-1) 2.n! 2x n=1 3+3 3.5.7.... (2n + 1) yan 2.n! n=1 (b) Use part (a) to find the Maclaurin series for 3 sin(x). be 3x + 3 3.5.7... (2n + 1) x + 1 n=1 (n + 1). 2".n! 3x + 3 2.4.6.... (2n) (2n + 1). 2.n! 2x2n + 1 n=1 0 3x + 3 1.3.5... 2.nl -(2n – 1) x2n + 1 n = 1 3x + 3 1.3.5... (n + 1). 2".n! (2n - 1) yn+1 n=1 3x + 3 1.3.5... (2n - 1) y2n + 1 n=1 (2n + 1). 2".n! -
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