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A box with a square base and open top must have a volume of 296352 cm. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only 2, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of x.] Simplify your formula as much as possible. A(x) = Next, find the derivative, A'(x). A'(x) = = Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by xº.) A'(x) = 0 when x = We next have to make sure that this value of a gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(:) Evaluate A"(x) at the x-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(z) is concave up around that value, so the zero of A'(x) must indicate a local minimum for A(z). (Your boss is happy now.)