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= Given the function g(x) = 4x3 – 187² – 48x, find the first derivative, g'(x). g'(x) = Notice that g'() = 0 when x = 4,
Posted: Tue May 10, 2022 6:57 pm
by answerhappygod
- Given The Function G X 4x3 187 48x Find The First Derivative G X G X Notice That G 0 When X 4 1 (53.03 KiB) Viewed 25 times
= Given the function g(x) = 4x3 – 187² – 48x, find the first derivative, g'(x). g'(x) = Notice that g'() = 0 when x = 4, that is, g'(4) = 0. Now, we want to know whether there is a local minimum or local maximum at x = : 4, so we will use the second derivative test. Find the second derivative, g"(x). g"(x) = = Evaluate g"(4). g"(4) = Based on the sign of this number, does this mean the graph of g(x) is concave up or concave down at x = 4? [Answer either up or down -- watch your spelling!!! At x = 4 the graph of g(x) is concave Based on the concavity of g(x) at x = 4, does this mean that there is a local minimum or local maximum at x = 4? [Answer either minimum or maximum -- watch your spelling!!! At x = 4 there is a local