Answer Happy

Photo Preview 024 (part 1 of 4) 10.0 points A function f is defined by f(x,y) = (x +8)(y - 3)(x + y - 4). - = (i) Determine fx for the function f. 1. fr(x, y) = (y - 3)(2x + y + 4) = 2. fr(2, y) = (2+8)(x - 2y + 4) x x ) = 3. fz(x, y) = (y - 3)(2x – y +12) 4. f(x, y) = (y +8)(2x + y + 12) 5. fr(x, y) = (x - 3)(x + 2y - 7) y – – =

< > Photo Preview 025 (part 2 of 4) 10.0 points (ii) Determine fy for the function f. 1. fy(2,y) (y + 3)(2x + y + 4) 2. fy(x, y) = (y - 3)(2x + y-7) - ) 3. fy(x,y) = (2+8)(x + 2y - 1) x = 4. f(x,y) = (x - 3)(x - 2y-7)

Photo 00 OO Preview 5. fy(x, y) = (2+8)(x + 2y – 7) 026 (part 3 of 4) 10.0 points (iii) Determine fxæ + fyy for the function f. 1. (fxx + fyy)(x, y) = x+y+5 = 2. (f22+ fyy)(x, y) = 2(x + y +5) fxx ( 3. (fxx + fyy)(x, y) 2(x + y +11) 4. (fxx + fyy)(x, y) = x +y +11 5. (fcx + fyy)(x, y) = 2(x + y - 11) 027 (part 4 of 4) 10.0 points (iv) Determine fxy for the function f. 1. fxy(x,y) = 2x + y - 15 2. fxy(x, y) = x + 2y + 1 3. fry(x,y) 2x + 2y +1 4. fxy(x, y) 2 2x + 2y +15 5. fxy(x,y) 2x + 2y - 15