A particle is in motion, and its acceleration at t sec is found to be a(t) = ( - sin(t))i + (-3+3+ + sin(t))j + (1 + cos

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answerhappygod
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A particle is in motion, and its acceleration at t sec is found to be a(t) = ( - sin(t))i + (-3+3+ + sin(t))j + (1 + cos

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A Particle Is In Motion And Its Acceleration At T Sec Is Found To Be A T Sin T I 3 3 Sin T J 1 Cos 1
A Particle Is In Motion And Its Acceleration At T Sec Is Found To Be A T Sin T I 3 3 Sin T J 1 Cos 1 (12.68 KiB) Viewed 30 times
A particle is in motion, and its acceleration at t sec is found to be a(t) = ( - sin(t))i + (-3+3+ + sin(t))j + (1 + cos(t) + sin(t))k. If it was at position ( - 4, – 4, 2) with velocity (-4, – 4, – 2) when t = 0, what are the velocity and position vectors when t = 1.2 sec?
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