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Use the limit comparison test to determine whether 7n3 – 5n2 +7 converges or diverges. 2 + 4n4 § an = n=7 n=7 Хю 1 (a) C
Posted: Tue May 10, 2022 6:23 pm
by answerhappygod
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Use the limit comparison test to determine whether 7n3 – 5n2 +7 converges or diverges. 2 + 4n4 § an = n=7 n=7 Хю 1 (a) Choose a series a bn with terms of the form bn - nP n=7 and apply the limit comparison test. Write your answer as a fully simplified fraction. For n > 7, an lim bn = lim n-> n-> (b) Evaluate the limit in the previous part. Enter @ as infinity and – as -infinity. If the limit does not exist, enter DNE. αη lim 7/3 bn n-> (c) By the limit comparison test, does the series converge, diverge, or is the test inconclusive? Converges