O 1 I 1 By Changing To Polar Coordinates Evaluate The Integral 2 I 527 I Sj Vx2 Y Dedy 3 I 537 When R Is 1 (26.44 KiB) Viewed 36 times
O 1 I 1 By Changing To Polar Coordinates Evaluate The Integral 2 I 527 I Sj Vx2 Y Dedy 3 I 537 When R Is 2 (20.75 KiB) Viewed 36 times
O 1. I = 1 By changing to polar coordinates evaluate the integral 2. I = 527 I= - SJ, Vx2 + y dedy 3. I = 537 when R is the region 4. I = 95.5 {(x,y): 4 5 ?? + y = 16,y 2 o} * 5. I = 21 62 in the cy-plane.
Evaluate the iterated integral 1. I = 1 2 I = Т" 4 sin(x2 + my?) dxdy + x 2. I = * 0 7T by converting to polar coordinates. 1 3. I 7T 4. I = 0 5. I = 2
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