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[15] (1) ηη 2 η n(η + 1)(2n + 1) 11 - - - k=2 Evaluate the sum: Useful Formulas: Σ1 = 1. Σ 1. Σ = (1 + 1), Ž[(k-1) – 8(k
Posted: Tue May 10, 2022 6:14 pm
by answerhappygod
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[15] (1) ηη 2 η n(η + 1)(2n + 1) 11 - - - k=2 Evaluate the sum: Useful Formulas: Σ1 = 1. Σ 1. Σ = (1 + 1), Ž[(k-1) – 8(k – 1) – 13] ΣΙ(4-1) - 8(x-1) -13] = Σ(Α' -8k -15) k=3 kFk+1 INDEX-SHIFT -(1-8-13) + (-86 – 13) ( Σ( = 20 +Σκ? - 8Σ -13 Σ1 2 12 k 8k =1 ADJUSTMENT k LINEARITY = 20 + 12.13-25 6. 8 ( 12 13) - 13:12 8 FORMULAS --- FACTORING 20 + 2.13.25 – 8-6 • 13 - 13.2.6 SIMPLIFYING 20 + 2•13 ( 25 – 406-6) 20 + 2013 (-5) 10 (2 - 13) = 10(-11) -110 FACTORING BE PAGES of (8)
[10] (1) (ης). Σκ' - +1 ΚΕ η(η + 1)( 2n + 1) 6 (A2 Evaluate the sum: Useful Formulas: Σ1 - 1. Σε ΣΙ(-2) - 6(k - 2) + 8]