Use partial fractions to find the power series of 4. 1 (x - 3)(x + 1) (1 - (-x)) 1/3 (1 – 2/3) 7+1 f() = x ^+1 201 3 n=0
Posted: Tue May 10, 2022 4:56 pm
Use partial fractions to find the power series of 4. 1 (x - 3)(x + 1) (1 - (-x)) 1/3 (1 – 2/3) 7+1 f() = x ^+1 201 3 n=0 f= +1 20 T=0 7-1 È (- ()* + (-1)--) f(x) = { (3n+1 + (−1)n+1) 2 3 * Σ) ()* -1)") È (-6)* +(-)*) - f(x) = [(-30-1 – (-1)+1) 2 f(x) = 5 +(-1)^+1 3 O f(2)= 1+1 3 22