Answer Happy

Given
R(1) = é cos(31) i+ è sin(31) j + 3e A
Find the derivative R' (t) and norm of the derivative.
Then find the unit tangent vector T(f) and the principal unit normal vectorN(t)
Then find the unit tangent vector T(f) and the principal unit normal vector
N(t)
Given R(t) = d cos(31) /+ é sin(3t); + 3e'k Find the derivative R' (t) and norm of the derivative. R'(t) = (-3e^(t) sin(3t)+e^(t)cos(3t))i +(3e^tcos(3t)+e^(t)sin( | || R'()|| = = sqrt((-3e^(t)sin(3t)+e^(t)cos(3t))^2 +(3e^tcos(3t)+e/ Then find the unit tangent vector T(1) and the principal unit normal vector NO) T(t) = ((-3e^(t) sin(31)+e^(t)cos(3t))i +(3e^tcos(3t)+e^(t)sin - NO N(O) = [(sqrt(10) (sin(3t)) + 3cos(3t))/10]i + [((sqrt10) (-3sin

Results for this submission Entered Answer Preview Result (-3d sin(31)+ d cos(30) /+ (3d cos(31) + sin(30) /+32* correct (-32 sin(31) + cos(31)) + (3d cos(31) + sin(3r)) + (3d)? correct 1-3"eh)*sin(3+6+(e^t)*cos(31))"+ [3"le^t)*cos(3*t)+(et)*sin(301*1*3* (et)'k sqrt{[-3"et* sin(31)+ (et)*cos(3*t)]^2)+(3 (e^*cos(3*t)+(e^t)*sin(3"t)]^2)+ ([3"(e]^2)) ((-3"let)*sin(3ºt)+(et)*cos(3*t)]*+ [3"le^t*cos(3ºt)+(et)*sin(3-0*43* (et)"kVísqrt((-39( et)"sin(3*t)+ le^t)*cos(3*t)]^2)+(3 (et)*cos(3*t)+(e^t)*sin(3ºt)]^2)+ ([3"^t)]^2)11 (-3e sin(3t) + e cos(31)) ++ (34 cos(31) + sin(30) / + 3et V(-3e' sin(31) + e' cos(31))? + (3e cos(31) + sin(311)2 + (3) correct VIO sin(31) + 3 cos(31) 7+ 10 V10(-3 sin(32) + cos(36)), (sqrt(10)*sin(3*t)+3*cos(3ºt)10)*l+ ([sqrt(10) [-3"sin(3*t)+cos(3*t)||/10)* incorrect 10 At least one of the answers above is NOT correct. (1 point) Given R(t) = d' cos(31) ; + &' sin(31) /+ 3e's Find the derivative R' (b) and norm of the derivative. R' (t) = (-3e^(t)sin(3t) + e^(t)cos(3t)i +(3e^tcos(31)+e"(t)sin( ||RO|| = sqrt((-3e^(t)sin(31)+ e^(t)cos(3t))^2 +(3etcos(31)+e/ Then find the unit tangent vector T(1) and the principal unit normal vector N(1) T(I) = ((-3e^(t)sin(3t)e^(t)cos(3)i +(3^tcos(31)+e"(t/sin N(I) = [(sqrt(10) (sin(31)) + 3cos(3t)/10]i + llsart 10) (-3sin