A. First, rewrite the integral by multiplying out the integrand: 3: z 13 3 z* (zB + 1) dx = dac Then evaluate the result

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A. First, rewrite the integral by multiplying out the integrand: 3: z 13 3 z* (zB + 1) dx = dac Then evaluate the result

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A First Rewrite The Integral By Multiplying Out The Integrand 3 Z 13 3 Z Zb 1 Dx Dac Then Evaluate The Result 1
A First Rewrite The Integral By Multiplying Out The Integrand 3 Z 13 3 Z Zb 1 Dx Dac Then Evaluate The Result 1 (44.04 KiB) Viewed 23 times
A. First, rewrite the integral by multiplying out the integrand: 3: z 13 3 z* (zB + 1) dx = dac Then evaluate the resulting integral term-by-term: 25 | 32 3z* (z® +1) dx = B. Next, rewrite the integral using the substitution w = +1: 3.7" (+ 1) dx = 5 37 dw Evaluate this integral (and back-substitute for w) to find the value of the original integral: 3* (25+1) dx = 3. C. How are your expressions from parts (A) and (B) different? What is the difference between the two? (answer from B)-(answer from A) = Are both of the answers correct?
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