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(e) jx X(1-x²)dx

Posted: Tue May 10, 2022 3:29 pm
by answerhappygod
E Jx X 1 X Dx 1
E Jx X 1 X Dx 1 (12.93 KiB) Viewed 16 times
the bottok nimber that is cutt off is 0
(e) jx X(1-x²)dx