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Find the zeros of the function y = (x2 + 2x - 5)(x3 + 2x2 – 15x). Number of solutions: fivev NOTE: Enter exact values for . X = X = V SE 7 X = X =

Use the graph of g(x) in the figure to the right to determine the factored form of y g(0) 2 13 g(x) = x4 – 4x3 – 4x2 + 16x. W +x 5 g(x)

Find a possible formula for a polynomial of degree four with zeros at (and only at) x = -4, 4, 5, and a y-intercept at y = 6, and long-run behavior of y = -oo as x++o. NOTE: There is more than one answer. Input only one. Answer must be exact. y =

. Find a possible formula for the polynomials with the given properties: g is fourth degree, g has a double zero at x = 2, g(5) = 0, 9(-3) = 0, g and g(0) = 2 NOTE: Enter the exact answer. g(x) =

Find a possible formula for the polynomials with the given properties: f is third degree with f(-1) = 0, $(2) = 0, $(4) = 0 and f(3) = 7. f(x) =

Find the real zeros (if any) of the polynomial y = x4 + 20x2 + 100. Input all zeros in the response box below separated by semicolons (;). If there are no zeros, input NA.

Find the real zeros (if any) of the polynomial y = ax" (x4 + 25)(x + 7), where a is a nonzero constant. = If there are no real zeros, enter NA in each entry area. Otherwise, enter your answers in increasing order. x = x =

y Give a possible formula of minimum degree for the polynomial h(x) displayed in the graph to the right. NOTE: Enter the exact answer. 3 2 -3 2 --2 3 h(21) = x =

- Suppose f(x) has zeros at x = -1, x = 6, x = 9 and a y-intercept x of 11. In addition, f(x) has the following long-run behavior: as x + too, y = . Find the formula for the polynomial f(x) which has the minimum possible degree. f(x) =

Give the domain for g(x) = In(3(x – 4)+(x + 1)). = - The domain of g is all x except x = = i