Details Sprecalc7 1 8 002 Smaller Value And 5 Larger Value Are Zeros Of 1 6 To Solve The Nonlinear Inequality S 1 (24.99 KiB) Viewed 24 times
Details Sprecalc7 1 8 002 Smaller Value And 5 Larger Value Are Zeros Of 1 6 To Solve The Nonlinear Inequality S 2 (24.99 KiB) Viewed 24 times
DETAILS SPRECALC7 1.8.002. (smaller value) and 5 (larger value) are zeros of 1.6 To solve the nonlinear Inequality *** so, we first observe that the numbers 3 divide the real line into three intervals. Complete the table. Interval 1) Sign of x + 3 Sign of x Sign of (x + 3)/(x - 5) )) 1...) v v 5 . Do any of the endpoints fail to satisfy the inequality Yes О No If so, which one()? (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE) 5 Find the solution of the inequality. (Enter your answer using interval notation> [ -3,5)
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