(3 5 19 18) [1 0 3 11 4 114 7 15) A= 0 1 3 0 1 2 3 U= 0 0 0 0 in reduced row echelon form is row equivalent to A. [2 3 1
Posted: Tue May 10, 2022 6:37 am
PLEASE ANSWER ALL PARTS OF THE QUESTION
(3 5 19 18) [1 0 3 11 4 114 7 15) A= 0 1 3 0 1 2 3 U= 0 0 0 0 in reduced row echelon form is row equivalent to A. [2 3 12 11 0 0 0 0 3 Denote the four columns of A by C1 = 18 7 3 C2 = 19 14 2 12 C3 = C4 = 0 11 a) Find a basis of the null space of the matrix A, and state the dimension of the null space. (6 PTS) A basis is Dimension = b) Find a basis of the column space of the matrix A, and state dimension of the column space. (You may use the column symbols C, C2, C3, C4 above in writing your answer.) (3 PTS) A basis is Dimension c) Find a basis of the row space of the matrix A, and state dimension of the row space. (You can write the basis vectors as horizontal rows.) (3 PTS) A basis is Dimension =
(3 5 19 18) [1 0 3 11 4 114 7 15) A= 0 1 3 0 1 2 3 U= 0 0 0 0 in reduced row echelon form is row equivalent to A. [2 3 12 11 0 0 0 0 3 Denote the four columns of A by C1 = 18 7 3 C2 = 19 14 2 12 C3 = C4 = 0 11 a) Find a basis of the null space of the matrix A, and state the dimension of the null space. (6 PTS) A basis is Dimension = b) Find a basis of the column space of the matrix A, and state dimension of the column space. (You may use the column symbols C, C2, C3, C4 above in writing your answer.) (3 PTS) A basis is Dimension c) Find a basis of the row space of the matrix A, and state dimension of the row space. (You can write the basis vectors as horizontal rows.) (3 PTS) A basis is Dimension =