An object of mass m = 9.4 kg is traveling in uniform circular motion at linear speed v = 16.1 ms under centripetal forc
Posted: Mon May 09, 2022 6:03 pm
An object of mass m = 9.4 kg is
traveling in uniform circular motion at linear
speed v = 16.1 ms under centripetal
force of F = 69.5 N. If the same object is
again traveling in uniform circular motion with the same linear
speed, but the centripetal force is increased by a factor
of β = 12, then the new radius of the object’s
trajectory, Rnew, will be γ times the
original radius, R. i.e. Rnew=γR . What
is γ? Round your answer to 2 decimal
places.
An object of mass m = 9.4 kg is traveling in uniform circular motion at linear speed v = 16.1 m under centripetal force of F = 69.5 N. If the same object is again traveling in uniform circular motion with the same linear speed, but the centripetal force is increased by a factor of B = 12, then the new radius of the object's trajectory, Rnew, will be y times the original radius, R. i.e. Rnew =yR. What is ? Round your answer to 2 decimal places.
traveling in uniform circular motion at linear
speed v = 16.1 ms under centripetal
force of F = 69.5 N. If the same object is
again traveling in uniform circular motion with the same linear
speed, but the centripetal force is increased by a factor
of β = 12, then the new radius of the object’s
trajectory, Rnew, will be γ times the
original radius, R. i.e. Rnew=γR . What
is γ? Round your answer to 2 decimal
places.
An object of mass m = 9.4 kg is traveling in uniform circular motion at linear speed v = 16.1 m under centripetal force of F = 69.5 N. If the same object is again traveling in uniform circular motion with the same linear speed, but the centripetal force is increased by a factor of B = 12, then the new radius of the object's trajectory, Rnew, will be y times the original radius, R. i.e. Rnew =yR. What is ? Round your answer to 2 decimal places.