Answer Happy

these are answers from 1-5 so it can help you answer questions through 6-10
6. Transform the 8 digits in your birthdate from Question 1 by subtracting the mean you computed in Question 2 from each digit. Report the resulting set of transformed scores. (Hint: For the N=8 digits in your birthdate from Question 1. you should get 8 corresponding transformed scores -- one for each of the original 8 digits in your birthdate from Question 1. Note that some of these mean deviations will be positive and some will be negative. The sign matters! Question for thought: Why are some of these mean deviations negative and some of them positive ?) 7. Compute the mean of the 8 transformed scores you obtained in Question 6. (Hint: You should get 0. Question for thought: Why will you always get O for the mean of the mean deviatichs ?) 8. First, square each of the Nu8 transformed scores that you obtained in Question 6. Then compute the mean of the resulting 8 squared scores. (NOTE: This "average squared mean deviation is called the variance. We will discuss the variance in the next section of this class, and it will be central to everything we do for the semester) 9. List all possible unique samples of size ne6 that you can draw from the N=8 digits in your birthdate from Question 1. For each sample of size n-6 digits that you list, compute the mean of that sample of digits. (Hint: there is a total of 28 different ways to choose a sample of n-6 digits from the total Nu& digits in your birthdate from Question 1. So you should get 28 samples of size na 6 for your answer to Question 9, and 28 means for those 28 samples.) 10. What is the mean of the 28 sample means that you computed in Question 9? How does it compare to the mean of the 8 digits in your birthdate that you computed in Question 2 Thi ha
Done Answer 1 of 1 Note: According to the guidelines, only first four subparts have been solved. To get the remaining please resubmit the question with subparts mentioned The data is given as: Date of birth data (X) = 1,2,0,1,2,0,0,0 Sample size of X is 8,n=8 Id number (Y) = 9,18,7,4,6,9,77 Sample size of Yis 9,m=9 2) Calculation of mean: Mean Mean == 0,75 Arrange the data in ascending order: X = 00001122 Calculation of median (when sample size is even): (M) + ( + 1) Median 2 2 m 9 (") + ( + 1)* Median = 4 (4) + (5) Median Median 0+1 0.5 Calculation of mode: O comes highest number of times. Therefore, mode is o Mean ΣΥ 3) Calculation of mean: 58 Mean = = 6.444 Arraange the data in ascending order: Y=146777889 Calculation of median (when sample size is odd): Median = (* 1 en Median = P 713 Median = (5) Median=1 Calculation of mode: 7 comes highest number of times. Therefore, mode is 7 4) Mean is greater than the median. Therefore, the distribution is positively skewed. 5) Mean is less than the median. Therefore, the distribution is negatively skewed.