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Calculate the pH after the addition of 45.86 mL of KOH in the titration of 45.86 mL of 0.157 M HNO, with 0.157 M KOH K f
Posted: Mon May 09, 2022 3:59 pm
by answerhappygod
- Calculate The Ph After The Addition Of 45 86 Ml Of Koh In The Titration Of 45 86 Ml Of 0 157 M Hno With 0 157 M Koh K F 1 (25.69 KiB) Viewed 20 times
Calculate the pH after the addition of 45.86 mL of KOH in the titration of 45.86 mL of 0.157 M HNO, with 0.157 M KOH K for HNO2 = 6.0x10-4 Answer: Check For which of the following is the equilibrium constant called the "K, of H2POA"? Select one: a. H2PO4 (aq) + H2O(1) = HPO 2(aq) + H2O*(aq) b. HPO ? (aq) + H200) = PO 3(aq) + H2O* (aq) C. PO - (aq) + H2O(0) = HPO 2 (aq) + OH(aq) d. HPO 2 (aq) + H2O(1) + H2PO4 (aq) + OH(aq) e. H3PO4 (aq) + H2O() + H2PO4 (aq) + H3O+ (aq) Check