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A sample of hellum gas in a balloon cocuples a volume of 4.80 x 10mL(480ml.) 1.23 atm pressure. What would be the pressu

Posted: Mon May 09, 2022 3:57 pm
by answerhappygod
A Sample Of Hellum Gas In A Balloon Cocuples A Volume Of 4 80 X 10ml 480ml 1 23 Atm Pressure What Would Be The Pressu 1
A Sample Of Hellum Gas In A Balloon Cocuples A Volume Of 4 80 X 10ml 480ml 1 23 Atm Pressure What Would Be The Pressu 1 (33.35 KiB) Viewed 27 times
A sample of hellum gas in a balloon cocuples a volume of 4.80 x 10mL(480ml.) 1.23 atm pressure. What would be the pressure in atm exerted by the pas if the balloon rises up in the air and volume of the balloon is changes to 647x10 ml. (647. mL) with no change in temperature. Calculate the new pressure in atm. Name tho yan Law. (5 points) Name of the gas Law Calculation steps Table of given values Equation and rearranged Eq. Bonus Question: (5 Points) Sodium azide (NaN,) decomposes to form N, gas in automobile collision by the following reaction. Calculate the volume of Na produced when if 38.5 g of NaN, decomposes in this reaction at 88°C and 1.32 atm. Name the gas Law. (Molar mass of NaN, is 65.02g, and R=0.0821 L-atmn/mol-K) 2NaN, (s) + 2 Na(s) + 3N, (g) Name of the gas Law Calculation Steps Table of given values Equations and Rearranged Eq. (1)