0.500 mol of each of H2S(9) and 12(9) are placed in a 1.00-L flask and allowed to react as H2S(g) + 1260) --S(s) + 2 HI(
Posted: Mon May 09, 2022 3:39 pm
0.500 mol of each of H2S(9) and 12(9) are placed in a 1.00-L flask and allowed to react as H2S(g) + 1260) --S(s) + 2 HI(g), with Kc = 1.15*10-2 What will be the concentration of Hl at equilibrium? 1.0.0508 M 2.0.0.0813 M 3.0.150 M 4.0.0254 M 5.0.0407 M