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Calculate the pH after the addition of 45,86 mL of KOH in the titration of 45.86 mL of 0.157 M HNO2 with 0.157 M KOH. K,
Posted: Mon May 09, 2022 3:24 pm
by answerhappygod
- Calculate The Ph After The Addition Of 45 86 Ml Of Koh In The Titration Of 45 86 Ml Of 0 157 M Hno2 With 0 157 M Koh K 1 (27.7 KiB) Viewed 30 times
Calculate the pH after the addition of 45,86 mL of KOH in the titration of 45.86 mL of 0.157 M HNO2 with 0.157 M KOH. K, for HNO2 = 6.0x10-4 Answer: Check For which of the following is the equilibrium constant called the "Ko of H2PO."? Select one: a. H2PO4 (aq) + H20(1) = HPO 2- (aq) + H2O*(aq) b. HPO - (aq) + H2O(l) = PO 3(aq) + H30* (aq) C. PO43-(aq) + H2O(l) =HPO42" (aq) + OH" (aq) d. HPO 2. (aq) + H2O(1) = H2PO4" (aq) + OH(aq) e. H3PO4 (aq) + H2O(1) = H2PO2 (aq) + H2O*(aq) + Check