Answer Happy

(6) Non-Planar Equilibrium with Fixed Connection (10 pts) Relevant Reading: Table 4.2 (entry 7) and Section 5.5 B T = 4000 N T = 4000 N 24 m 24 m M AZ May m 3 m 15 m 15 m FAY Fixed connection 2 m 2 m Faz Max c 0 10 m 10 m X X The associated free-body diagram of the crane. A construction-crane is acted on by a 4000-N cable force. The cable force, written in vector notation is: T=2443 Ni+1578 Ni - 2747 Nk у (a) Based on the free-body diagram, write-out the three force equilibrium Equations (5.3A, 5.3B, 5.3C) for this System: ΣF, = 0; ΣΕ, = 0; ΣF = 0; (b) Based on the free-body diagram, write-out the three moment equilibrium Equations (5.4A, 5.4B, 5.4C) for this system: M = 0; M = 0; M = 0; (hint: to make calculations easier, first determine (rABX T) OR (Tacx T before writing the individual moment equilibrium equations). (c) Use the equilibrium equations from (a) and (b) to determine the six unknowns FA FA FA and M4, M4v> MA