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df F 39.70046983 1 SS 1815.5782 1280.4934 3096.0716 MS 1815.5782 45.73190714 28 29 1 ANOVA table 2 Source 3 Regression 4

Posted: Mon May 09, 2022 12:13 pm
by answerhappygod
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 1
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 1 (38.9 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 2
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 2 (129.95 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 3
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 3 (63.56 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 4
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 4 (49.23 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 5
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 5 (57.57 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 6
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 6 (63.72 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 7
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 7 (44.95 KiB) Viewed 22 times
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 8
Df F 39 70046983 1 Ss 1815 5782 1280 4934 3096 0716 Ms 1815 5782 45 73190714 28 29 1 Anova Table 2 Source 3 Regression 4 8 (62.19 KiB) Viewed 22 times
df F 39.70046983 1 SS 1815.5782 1280.4934 3096.0716 MS 1815.5782 45.73190714 28 29 1 ANOVA table 2 Source 3 Regression 4 Residual 5 Total 6 6 7 7 8 Regression output 9 Variables 10 Intercept 11 Distance-X Coefficients 14.75325 3.4332 Std. Error 3.118 0.544880519 t(df=28) 3.508 6.3

Waterbury Insurance Company wants to study the relationship between the amount of fire damage and the distance between the burning house and the nearest fire station. This information will be used in setting rates for insurance coverage. For a sample of 30 claims for the last year, the director of the actuarial department determined the distance from the fire station (x) and the amount of fire damage, in thousands of dollars (%). The MegaStat output is reported here: ANOVA table Source Regression Residual Total SS 1,815.5782 1,280.4934 3,096.0716 df 1 28 29 00 PM N N MS F 1,815.5782 39.7005 45.7319 Regression output Variables Coefficients Intercept 14.7532 Distance-X 3.4332 Std. Error 3.118 0.5449 t(df=28) 3.508 6.3 Click here for the Excel Data File Required: a-1. Determine the regression equation. (Round your answers to 3 decimal places.) y = X.

a-2. Is there a direct or indirect relationship between the distance from the fire station and the amount of fire damage? The relationship between distance and damage is direct. indirect. b. How much damage would you estimate for a fire 5 miles from the nearest fire station? (Round your answer to the nearest dollar amount.) Estimated damage

C-1. Determine and interpret the coefficient of determination. (Round your answer to 3 decimal places.) Coefficient of determination c-2. Fill in the blank below. (Round your answer to one decimal place.)| % of the variation in damage is explained by variation in distance.

d-1. Determine the correlation coefficient. (Round your answer to 3 decimal places.) Correlation coefficient d-2. Choose the right option. There is a fairly solid link between the variables. direct indirect

d-3. How did you determine the sign of the correlation coefficient? It is because the slope is positive negative . e-1. State the decision rule for 0.01 significance level: Ho: p = 0; H1 : 0#0. (Negative value should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject Ho ift< or t>

e-2. Compute the value of the test statistic. (Round your answer to 2 decimal places.) Value of the test statistic e-3. Is there any significant relationship between the distance from the fire station and the amount of damage? Use the 0.01 significance level. Ho. There is relationship between distance and fire damage. significant no significant

The following sample observations were randomly selected. X: 8 5 13 3 15 بیا ی 6 7 3 12 4 13 4 11 6 9 U 00 y: a. Determine the 95% confidence interval for the mean predicted when x = 7. (Round your answers to 4 decimal places.) b. Determine the 95% prediction interval for an individual predicted when x = 7. (Round your answers to 4 decimal places.)