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Posted: **Mon May 09, 2022 11:16 am**

: N Na 1 Cos 10 6 Points We Proved In Recitation That For X 2nn N E Z Cos Kx None Sin N 237 Sin K 0 Use T 1 (38.01 KiB) Viewed 39 times

n na (1) COS 10. (6 points) We proved in recitation that for x # 2nn, n e Z, cos(kx) (none) sin( n +237) sin() k=0 Use this to show that cos(kx) x2 + k converges uniformly on an interval [8, 21 – 8] for any 8 k=0 with 0 < d <.