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1 1 point The stress-strain curve below represents experimental data. The value of slope E = 80 GPa while the values of

Posted: Mon May 09, 2022 10:27 am
by answerhappygod
1 1 Point The Stress Strain Curve Below Represents Experimental Data The Value Of Slope E 80 Gpa While The Values Of 1
1 1 Point The Stress Strain Curve Below Represents Experimental Data The Value Of Slope E 80 Gpa While The Values Of 1 (313.63 KiB) Viewed 24 times
1 1 point The stress-strain curve below represents experimental data. The value of slope E = 80 GPa while the values of p and q are 0.85 and 0.7, respectively. The stress op = 20MPa, while the value of 0g = 26MPa. Which of the following represent the material's elastic modulus and 0.2% offset yield? ор. PE TE JE ОООО elastic modulus = 160 GPa 0.2% offset yield strength = 20 MPa elastic modulus = 160 GPa 0.2% offset yield strength = 26 MPa elastic modulus = 100 GPa 0.2% offset yield strength = 26 MPa elastic modulus = 80 GPa 0.2% offset yield strength = 26 MPa 2 > 1 point For measured points including p=0.85 and q = 0.7, the Ramberg-Osgood equation takes the form: <= ()(1+(1)(a)") where n = 1+ In(4) In02 What strain does the Ramberg-Osgood equation predict for an applied stress equal to the 0.2% yield stress? 4.64E-4 3.88E-5 2.58E-6 8.99E-3 3 1 point The parameter n in the Ramberg-Osgood equation gives a measure of work-hardening, which is the process by which plastic deformation (plastic strain) increases the stress required to achieve additional plastic deformation. A larger ratio of measured stresses 90.7 to 0.85 indicates a greater capacity for work hardening. True False 4 1 point In the case of a particular uniaxial tensile test, the values of 90.7 and 80.85 are identical within experimental error. This material has a Ramberg-Osgood parameter n= infinity, indicating elastic, perfectly plastic behavior. This material would not display any significant work hardening during plastic deformation True o False