Page 1 of 1
For the But network below. Ve = 14V. R. = 68.402. R. = 1020, R = 120, 5.5.2001 R: = 0,82 k2, R. = 3,3 40, C, = 0.474F.C.
Posted: Mon May 09, 2022 8:38 am
by answerhappygod
- For The But Network Below Ve 14v R 68 402 R 1020 R 120 5 5 2001 R 0 82 K2 R 3 3 40 C 0 474f C 1 (32.22 KiB) Viewed 20 times
For the But network below. Ve = 14V. R. = 68.402. R. = 1020, R = 120, 5.5.2001 R: = 0,82 k2, R. = 3,3 40, C, = 0.474F.C. - Spf.C.-8pF.C = 12pF.č. = 40pF.C.=8pF. C=0.474F.C = 204F. -120. (total 12 points) a. Determine Sandf, 15 points) b. Determine fs, and S. 15 points) What is the lower cutoff frequency and higher cutoff frequency of the amplifier?12 points) С. Voc 140 Rp 85.6kr 63 HA 0.47UF 0.47 uF HH R 20.821 R. 23.3k V R₂ lokn W RE CE zouf E 1.2k = = solution: