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VCC 18V RC R1 27ko C1 16 1uF Rs w 6000 C2 11 2.2pF 01 2N2222A BDC = 220 RL Bac = 220 Vs 100mVrms 1kHz 0° R2 3.9k RE1 RE2
Posted: Mon May 09, 2022 7:45 am
by answerhappygod
- Vcc 18v Rc R1 27ko C1 16 1uf Rs W 6000 C2 11 2 2pf 01 2n2222a Bdc 220 Rl Bac 220 Vs 100mvrms 1khz 0 R2 3 9k Re1 Re2 1 (43.12 KiB) Viewed 26 times
VCC 18V RC R1 27ko C1 16 1uF Rs w 6000 C2 11 2.2pF 01 2N2222A BDC = 220 RL Bac = 220 Vs 100mVrms 1kHz 0° R2 3.9k RE1 RE2 w C3 47F Q Calculate the value of the internal admittance of the BJT transistor in the circuit r'e = [ ] 12, given that le = 4.76 mA. Also NOTE: Only place the value of the answer in the answer space do not put the S.I Units in the answer space given.