a meter stick is supported 35cm from its left end. It has a 15N weight hung 20cm from the left end and an 8N weight hung
Posted: Fri May 06, 2022 1:13 pm
a meter stick is supported 35cm from its left end. It has a 15N weight hung 20cm from the left end and an 8N weight hung to the right of the support. Find the force of the support at 35cm and the distance from the left end of the stick where 8N weight should be hung for equilibrium.
Pic here for better understanding. Please help me understand this problem I missed.
meter stick Im is 100cm 15 pts) A meter stick is supported 35 cm from its left end. It has a 15 N weight hung 20 cm from the left nd and an 8 N weight hung to the right of the support. Find the force of the support (at 35 cm) and the stance from the left end of the stick where the 8 N weight should hung for equilibrium. moment arm ***gem A mium Find the force of the support at 35cm .2m 35 cm 15 N (23) x-8₁ (.35m) - 15 w (₁) = (0 (23) x=2.8 Nom - 15 Nom = 0 @ 20 cm 42.8 2 (23) X-17.80 N. m = 0 X 2 17.800m 2 0.77 C.O.G M 23~ -5,8 15N+8~ F= 23 X = 63.1cm 8 N @?cm
Pic here for better understanding. Please help me understand this problem I missed.
meter stick Im is 100cm 15 pts) A meter stick is supported 35 cm from its left end. It has a 15 N weight hung 20 cm from the left nd and an 8 N weight hung to the right of the support. Find the force of the support (at 35 cm) and the stance from the left end of the stick where the 8 N weight should hung for equilibrium. moment arm ***gem A mium Find the force of the support at 35cm .2m 35 cm 15 N (23) x-8₁ (.35m) - 15 w (₁) = (0 (23) x=2.8 Nom - 15 Nom = 0 @ 20 cm 42.8 2 (23) X-17.80 N. m = 0 X 2 17.800m 2 0.77 C.O.G M 23~ -5,8 15N+8~ F= 23 X = 63.1cm 8 N @?cm