You poor yourself a cold glass (m = 0.6 kg) of ice tea (m = 1.2 kg) on a hot summer day and accidently leave it in the s
Posted: Fri May 06, 2022 12:47 pm
You poor yourself a cold glass (m = 0.6 kg) of ice tea (m = 1.2
kg) on a hot summer day and accidently leave it in the sun, which
causes both the tea and the glass to warm up to a temperature of 19
degrees C. You want to bring it down both down to a nice cold 1
degree C before you drink it. What mass of ice at -15 degrees C do
you need to add to the system to cool it down? Assume, the specific
heat of water and tea is 4186 J/kg degrees C, the specific heat of
the cup is 837 J/kg degrees C, the specific of ice is 2090 J/kg
degrees C, and the latent heat of fusion for ice to water is 3.34 x
10^5 J/kg.
kg) on a hot summer day and accidently leave it in the sun, which
causes both the tea and the glass to warm up to a temperature of 19
degrees C. You want to bring it down both down to a nice cold 1
degree C before you drink it. What mass of ice at -15 degrees C do
you need to add to the system to cool it down? Assume, the specific
heat of water and tea is 4186 J/kg degrees C, the specific heat of
the cup is 837 J/kg degrees C, the specific of ice is 2090 J/kg
degrees C, and the latent heat of fusion for ice to water is 3.34 x
10^5 J/kg.