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Review | Constants. Part A How long after closing the switch will the current through the inductor reach one-half of its maximum value? Express your answer with the appropriate units. to.5 max current = 17.3 us Submit Previous Answers ✓ Correct IDENTIFY: i = E/R(1 - e-t/¹), with 7 = L/R. The energy stored in the inductor is U = 1/Li². SET UP: The maximum current occurs after a long time and is equal to E/R. EXECUTE: imax = {/R so i = imax/2 when (1 - e-t/¹) = 1/2 and e-t/T =1/1. .-t/T = ln(/). t= L In 2 R (In 2) (1.25x10-³ H) 50.0 Ω = 17.3 μs. Part B How long after closing the switch will the energy stored in the inductor reach one-half of its maximum value? Express your answer with the appropriate units. μÀ ? to.5 max energy = Value S P Pearson Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | A 35.0 V battery with negligible internal resistance, a 50.0 resistor, and a 1.25 mH inductor with negligible resistance are all connected in series with an open switch. The switch is suddenly closed. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Analyzing an r-l circuit.