Page 1 of 1
A mass m₁ of steam at 100 °C is added to mass m₂ of ice and mass M of water, both at 0 °C, in a container of negligible
Posted: Fri May 06, 2022 10:56 am
by answerhappygod
- A Mass M Of Steam At 100 C Is Added To Mass M Of Ice And Mass M Of Water Both At 0 C In A Container Of Negligible 1 (156.42 KiB) Viewed 33 times
A mass m₁ of steam at 100 °C is added to mass m₂ of ice and mass M of water, both at 0 °C, in a container of negligible heat capacity. The specific heat of water is c. The latent heat of vaporization of water is L₁ and that of the fusion of ice is L2. Which one of the following equations would give the value of T, the final temperature of the system, assuming that all the steam condenses, all the ice melts, and that there are no heat exchanges with the surroundings? Om₁L₁+m₁c( 100-T) = m₂L2+ m₂cT + McT OmL +mic(100-T) = m₂L2 + McT Om₁L₁+m₁c(100-T) = m₂L₂+ m₂cT Om₁L₁+m₁cT= m₂L2+ m₂cT + McT O mic(100-T)= m₂L₂ + McT