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4) A gold coin weighs 0.30478 N in air. The gold coin submerged in water weighs 0.01244 N. The density of water is 1000k

Posted: Fri May 06, 2022 10:29 am
by answerhappygod
4 A Gold Coin Weighs 0 30478 N In Air The Gold Coin Submerged In Water Weighs 0 01244 N The Density Of Water Is 1000k 1
4 A Gold Coin Weighs 0 30478 N In Air The Gold Coin Submerged In Water Weighs 0 01244 N The Density Of Water Is 1000k 1 (20.51 KiB) Viewed 29 times
4 A Gold Coin Weighs 0 30478 N In Air The Gold Coin Submerged In Water Weighs 0 01244 N The Density Of Water Is 1000k 2
4 A Gold Coin Weighs 0 30478 N In Air The Gold Coin Submerged In Water Weighs 0 01244 N The Density Of Water Is 1000k 2 (24.33 KiB) Viewed 29 times
4 A Gold Coin Weighs 0 30478 N In Air The Gold Coin Submerged In Water Weighs 0 01244 N The Density Of Water Is 1000k 3
4 A Gold Coin Weighs 0 30478 N In Air The Gold Coin Submerged In Water Weighs 0 01244 N The Density Of Water Is 1000k 3 (15.76 KiB) Viewed 29 times
4) A gold coin weighs 0.30478 N in air. The gold coin submerged in water weighs 0.01244 N. The density of water is 1000kg/m³. The density of gold is 19.3 x 10³ Kg/m³. Is the coin made of pure gold? 5) 10 m³/hour of water flows through a 100 mm diameter pipe. Determine the velocity of water if the pipe is reduced to 80 mm in diameter?
4) Density Con 19.292 X18 kg/m³ 5) 0.55m/sec = V/₂
Where Po = weight of air at sea level = 1.01 X 105 Pa Density mass/volume Pascal's Principal Equation of Continuity Equation of Continuity for incompressible fluid Bernoulli's Equation P₁ = P₁+pgh₁ p = m/V F₁/A₁=F₂/A₂ P₁A₁V₁ = P₂A₂V2 A₁V₁= A₂V₂ P + pv₁² +pgy = constant P₁ + ½ pv₂² +p gy₁ = P₂ + ½ pv₁2 +p gy2 Bernoulli's Equation 110-1 *.*. -H FIL mu