Iodine undergoes a decay process as follows: ¹241 → Te + e+ + v. Rewrite this reaction, filling in the missing numbers.
Posted: Fri May 06, 2022 10:27 am
Iodine undergoes a decay process as follows: ¹241 → Te + e+ + v. Rewrite this reaction, filling in the missing numbers. Help chemPad XX Greek What sort of decay is this? O inverse beta decay O alpha decay O beta decay