An object is moving in a circular motion law: s(t)=2t^3=3t^2+4. In t=2s, the module of its total acceleration is a=40m/
Posted: Fri May 06, 2022 10:07 am
An object is moving in a circular motion law:
s(t)=2t^3=3t^2+4. In t=2s, the module of its total acceleration is
a=40m/s^2
Compute the Radius R of the circle. Compute the module of the
acceleration in t=1s.
s(t)=2t^3=3t^2+4. In t=2s, the module of its total acceleration is
a=40m/s^2
Compute the Radius R of the circle. Compute the module of the
acceleration in t=1s.