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We wish to make a buffer solution at a pH of 9.50. Which of the following acids and its conjugate base salt would be mos

Posted: Fri May 06, 2022 8:27 am
by answerhappygod
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 1
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 1 (15.12 KiB) Viewed 28 times
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 2
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 2 (21.93 KiB) Viewed 28 times
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 3
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 3 (34.08 KiB) Viewed 28 times
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 4
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 4 (30.22 KiB) Viewed 28 times
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 5
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 5 (14.04 KiB) Viewed 28 times
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 6
We Wish To Make A Buffer Solution At A Ph Of 9 50 Which Of The Following Acids And Its Conjugate Base Salt Would Be Mos 6 (6.15 KiB) Viewed 28 times
We wish to make a buffer solution at a pH of 9.50. Which of the following acids and its conjugate base salt would be most helpful? CH3COOH K₂= 1.8 x 10-5 C6H₂COOH K₂= 6.14 x 10-5 CICH₂COOH K₂= 1.36 x 10-³ CoH5OH K₂= 1.6 x 10-10 O
Which of the following mixtures would result in a buffered solution? Mixing 100.0 mL of 0.100 MHCI with 100.0 mL of 0.100 M NaOH. Mixing 100.0 mL of 0.100 M NH3 (K₁ = 1.8 x 10-5) with 100.0 mL of 0.100 M NaOH. Mixing 100.0 mL of 0.100 MHCI with 100.0 mL of 0.100 M NH 3 Kb = 1.8 x 10-5. Mixing 100.0 mL of 0.100 M NH4Cl with 100.0 mL of 0.100 MNH3 Kb = 1.8 x 10-5.
The following thermodynamic data are available for the following reaction: 2H2S(g) + 302(g) →2SO2(g) + 2H₂O(g) ΔΗ, (kJ/mol) S° (J/mol-K) H₂S(g) -20.6 205.8 0218 0 205.2 -296.8 248.2 H₂O(g) -241.8 188.8 a) Calculate AH for the reaction. AH° rxn -EnAH (products) -EnAH°f(reactants) (3 pts) b) Does AH favor spontaneity? (Explain) (2 pts) c) Calculate AS for the reaction. AS rxnE nAS (products) - EnAS (reactants) (3 pts) d) Does AS favor spontaneity? (Explain) (2 pts) e) Calculate AG for the reaction at 25°C. Is the reaction spontaneous (explain)? SO2(8)
H₂O(g) -241.8 a) Calculate AH for the reaction. AH° rxn EnAH°f(products) -EnAH°(reactants) (3 pts) b) Does AH favor spontaneity? (Explain) (2 pts) c) Calculate AS for the reaction. AS rxn= E NAS (products) - EnAS (reactants) (3 pts) d) Does AS favor spontaneity? (Explain) (2 pts) e) Calculate AG for the reaction at 25°C. Is the reaction spontaneous (explain)? (5 pts) AG=AH-TAS f) Calculate, if possible, or explain the temperature range at which the reaction will be spontaneous. Teq = AH/AS 188.8
The Ka of benzoic acid, C6H5COOH is 6.30 x 105. The equation for the K₂ is: C6H5COOH (aq) + H₂O(1) C6H5COO (aq) + H30* (aq) a) What is the [H3O+] and [OH-] in a 1.25 M solution? b) What is the pH and pOH of the solution? c) What are the equilibrium concentrations of H3O*, C6H5COOH, and C₂H5COO™
Calculate the pH of a solution made from .45M Benzoic acid and .55M Sodium Benzoate. The Ka of benzoic acid is 6.30 x 10-5.