Hello! I recently did an experiment for the formation of 2-Naphthalenol. 3.0 mmol of each reactant was used and the bala
Posted: Fri May 06, 2022 8:14 am
Hello! I recently did an experiment for the formation of
2-Naphthalenol. 3.0 mmol of each reactant was used and the balanced
chemical equation requires 1 of each reactant. How do I approach
finding a limiting reactant in this case? Thank you!
m-nitroaniline + 2-napthol → 2-Naphthalenol N NO₂ OH ∞ NH₂ Calculations Percent yield: Yield Calculations: Initial mass of m-nitroaniline: 0.4143g Initial moles of m-nitroaniline: 3.00 mmol Initial mass of 2-napthol: 0.4326g Initial moles of 2-napthol: 3.0 mmol Limiting reactant: + H
2-Naphthalenol. 3.0 mmol of each reactant was used and the balanced
chemical equation requires 1 of each reactant. How do I approach
finding a limiting reactant in this case? Thank you!
- Hello I Recently Did An Experiment For The Formation Of 2 Naphthalenol 3 0 Mmol Of Each Reactant Was Used And The Bala 1 (83.9 KiB) Viewed 40 times